Which option gives f(x) = x² - 4x - 12 rewritten in vertex form as well as the function's correct axis of symmetry ?
f(x) = (x - 2)² - 16, x = - 16
f?(x) = (x + 2)(x - 6), x = 6
f(x) = (x + 2)(x - 6), x = -2
f(x) = (x - 2)² - 16, x = 2

Respuesta :

y

=

(

x

2

)

2

+

16

is the vertex form

Explanation:

The vertex form of a quadratic function is given by

y

=

a

(

x

h

)

2

+

k

where (h, k) is the vertex of the parabola.

when written in vertex form

(h, k) is the vertex of the parabola and x = h is the axis of symmetry

the h represents a horizontal shift (how far left, or right the graph has shifted from x = 0)

the k represents a vertical shift (how far up, or down the graph has shifted from y = 0)

Now let convert this  

y

=

x

2

+

4

x

+

12

into vertex form

y

=

x

2

+

4

x

+

12

y

12

=

x

2

+

4

x

y

12

=

(

x

2

4

x

)

y

12

=

(

x

2

4

x

+

4

4

)

y

12

=

(

x

2

4

x

+

4

)

+

4

y

16

=

(

x

2

4

x

+

4

)

y

16

=

(

x

2

)

2

y

=

(

x

2

)

2

+

16

is the vertex form

show the vertex in the figure below

graph{-x^2+4x+12 [-10.06, 15.25, 6.58, 19.25]}   Hope iam right