Question

Supria and Elle live 21 miles apart. They leave their respective homes at the same time to go for

a jog. They begin running toward each other with the intent of meeting. Supria runs at a

constant rate of 8 miles per hour and Elle runs at a constant rate of 8 miles per hour. A third

friend starts at Supria's house and rides her bike toward Elle's house and rides her bike toward

Elle's house at a constant rate of 10 miles per hour. How far will the bicyclist have ridden when

Supria and Elle finally meet?

Answer 1

Answer:

$d3=13.125$ $miles$

Step-by-step explanation:

Given data:

$total$ $distance = 21$ $miles$

$s1=8$ $miles/hr$

$s2=8$ $miles/hr$

$s3=10$ $miles/hr$

First we have to find out the how much time it takes when Supria and Elle meet.

As we know,

$Displacement=rate*time$

$d1=s1*t$

$d2=s2*t$

$d1+d2=21$

$8t+8t=21$

$16t=21$

$t=21/16$

Now we can find that how much the third friend had traveled during this time period

$d3=s3*t$

$d3=10*21/16$

$d3=13.125$ $miles$