Question

You measure 3.03 mL of a 50% NaOH solution by weight (its density is 1.53 g mL-1) and dilute it to 500 mL total volume. What is the concentration of this NaOH solution? Write your answer to four decimal places (X.XXXX).

Answer 1

The concentration of the NaOH solution is 0.1186 moles/L. The concentration of a solution is measured in mole/L.

How to calculate the concentration?

To calculate the concentration of the NaOH first, calculate its mass,

$m = V d w$

Where,

m - mass

$v$ - volume of NaOH = 3.03 mL

$d$ - dencity = 1.53 g mL-1

$V$  - Total volume = 0.5 L

Put the values in the formula, we get,

m = 2.3715 g

The molar mass of NaOH is 40 g/mol.

Now calculate the number of moles,

$n = \dfrac {2.3715}{40}\\\\n = 0.0593$

So, the concentration of the NaOH solution,

$c = n/V$

$c =\dfrac {0.0593}{0.5}\\\\ c = 0.1186$

Therefore, the concentration of the NaOH solution is 0.1186 moles/L.

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