Answer: The mass percent of water in the original sample is 69.5 %
Explanation:
We are given:
Mass of NaCl remained after heating = 1.22 grams
Mass of the sample = 4.00 grams
Mass of water evaporated = Mass of sample - Mass of NaCl remained
Mass of water evaporated = (4.00 - 1.22) g = 2.78 grams
To calculate the mass percentage of water in the sample, we use the equation:
[tex]\text{Mass percent of water}=\frac{\text{Mass of water}}{\text{Mass of sample}}\times 100[/tex]
Mass of water = 2.78 g
Mass of sample = 4.00 g
Putting values in above equation, we get:
[tex]\text{Mass percent of water}=\frac{2.78g}{4.00g}\times 100=69.5\%[/tex]
Hence, the mass percent of water in the original sample is 69.5 %