Question

The probability is 0.271 that the gestation period of a woman will exceed 9 months. In 3000 human gestation​ periods, roughly how many will exceed 9​ months?

Answer 1

Answer:

813 will exceed 9 months.

Step-by-step explanation:

For each women, there are only two possible outcomes. Either they will exceed the gestation period, or they will not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

In this problem, we have that:

$n = 3000, p = 0.271$

In 3000 human gestation​ periods, roughly how many will exceed 9​ months?

$E(X) = np = 3000*0.271 = 813$

813 will exceed 9 months.

Answer 2

The gestation period should be exceed 9 month is 813.

Given that,

• The probability is 0.271 that the gestation period of a woman will exceed 9 months.
• And, there is 3000 human gestation​ periods

Based on the above information, the calculation is as follows:

$= 0.271 \times 3,000$

= 813

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