Answer:
F_e = +/- 0.013133 N
Explanation:
Given:
- charge on each sphere q = -56 nC
- separation of spheres r = 3.0 cm
- charge constant k = 8.99*10^9
Find:
- Magnitude of Electric Force F_e on each sphere.
Solution:
The magnitude of electric Force F_e of one sphere on other is:
F_e = k*q^2 / r^2
- Plugging the given values :
F_e = (8.99*10^9) * (56*10^-19)^2 / (0.03)^2
F_e = 0.013133 N
- An equal and opposite force is experienced on the other sphere. Hence, F_e = + / - 0.013133 N