Question

How many moles are contained in .250 grams of N-acetyl-p-toluidine? Enter only the number to three significant figures.

Answer 1

Answer: The amount of N-acetyl-p-toluidine is $1.68\times 10^{-3}mol$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of N-acetyl-p-toluidine = 0.250 g

Molar mass of N-acetyl-p-toluidine = 149.2 g/mol

Putting values in above equation, we get:

$\text{Moles of N-acetyl-p-toluidine}=\frac{0.250g}{149.2g/mol}=1.68\times 10^{-3}mol$

Hence, the amount of N-acetyl-p-toluidine is $1.68\times 10^{-3}mol$