Question

375 kJ is added to a 25.0 kg granite rock. How much does the temperature increase? NEED HELP SOLVING

Answer 1

Increase in temperature is $19.0^{\circ}C$

Explanation:

When heat is added to a substance, the temperature of the substance increases according to the equation

$Q=mC\Delta T$

where

Q is the amount of heat supplied

m is the mass of the substance

C is the specific heat capacity of the substance

$\Delta T$ is the change in temperature

For the granite rock in this problem, we have:

$Q=375 kJ = 375,000 J$

m = 25.0 kg

$C=790 J/kg^{\circ}C$ is the specific heat capacity of granite

And solving for $\Delta T$, we find the increase in temperature:

$\Delta T = \frac{Q}{mC}=\frac{375,000}{(25.0)(790)}=19.0^{\circ}C$

Learn more about specific heat:

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