Question

A 3.3×10-2 mg sample of a protein is dissolved in water to make 0.25 mL of solution. The osmotic pressure of the solution is 0.56 torr at 25°C. What is the molar mass of the protein?

Answer 1

Answer: 4376.6g/mol

Explanation:Please see attachment for explanation

Answer 2

The molar mass of the protein is 4376.6 g/mol.

What is molar mass?

The molar mass of a chemical compound is defined as the mass of a sample divided by the amount of substance in that sample, measured in moles.

Solution:

Given, the mass of protein is 3.3×10-2 mg

Mass converted into gram = 3.3×10-2 mg = M 0.000033 g

Therefore, xg of the protein dissolve in 1 L

xg pf protein =$\bold{\dfrac{0.000033}{0.00025} = 0.132\; g/L}$

Given, the osmotic pressure of 0.56 torr.

$\bold{\pi = 0.56\;torr =\dfrac{0.56}{760} = 0.00737\; atm p}$

Thus, the volume of the solution is 0.007 L

Given, Temperature = 25 °C

Converting into kelvin = 25+273 = 298 k.

R = 0.082 atm.

Now, by the formula  $\bold{M_2= \dfrac{W_2RT}{\pi V}}$

$\bold{M_2= \dfrac{0.132\times0.082\times298}{0.00737\times0.007} =4376.6 \;g/mol}$

Thus, the molar mass of protein is 4376.6 g/mol.

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