Respuesta :
Answer:
L_original = 28.8 in
H_original = 19.2 in
Step-by-step explanation:
Given:
- Length of scaled rectangle L_scale = 18 in
- width of the scaled rectangle H_scale= 12 in
- Scale factor = (5/8)
Find:
-Which method can be used to find the dimensions of the original rectangle
Solution:
- The best way to determine the original dimensions of the rectangle is by ratios. We have the scale factor as (5/8). so we can express:
L_scale = (5/8)*L_original
L_original = L_scale*(8/5)
L_original = 18*(8/5) = 28.8 in
H_scale = (5/8)*H_original
H_original = H_scale*(8/5)
H_original = 12*(8/5) = 19.2 in
- Hence, the original dimensions are:
L_original = 28.8 in
H_original = 19.2 in
Answer:
B. [tex]18 / \frac{5}{8}= 28\frac{4}{5}[/tex] [tex]inches[/tex] [tex]and[/tex] [tex]12 /\frac{5}{8} = 19\frac{1}{5}[/tex] [tex]inches[/tex]
Step-by-step explanation:
