Answer:
[tex]m\angle E=58^o[/tex]
Step-by-step explanation:
we know that
In the right triangle DEF
[tex]tan(E)=\frac{DF}{EF}[/tex] ----> by TOA (opposite side divided by adjacent side)
[tex]tan(E)=\frac{8}{5}[/tex]
[tex]m\angle E=tan^{-1}(\frac{8}{5})=58^o[/tex]