Answer:
Amy has 310 small marbles, 62 medium marbles and 188 large marbles.
Step-by-step explanation:
i) Let the number of small marbles be x
ii) let the number of medium marbles be y
iii) let the number of large marbles be z
iv) Amy has 5 times as many small marbles as medium marbles therefore we can write 5y = x
v) the number of large marbles is two more than than three times the number of medium marbles therefore we can write
z = 3y + 2
vi) Amy has a total of 560 marbles therefore we can write x + y + z = 560
vii) Therefore from i) we can write x = 5y
viii) using vii) and v) in vi) we can write
x + y + z = 5y + y + 3y + 2 = 560
ix) Therefore 9y = 558 .... therefore y = [tex]\frac{558}{9}[/tex] = 62
x) Therefore from i) we get x = y [tex]\times[/tex] 5 = 62 [tex]\times[/tex] 5 = 310
xi) Therefore z = (3 [tex]\times[/tex] 62) + 2 = 188
Amy has 310 small marbles, 62 medium marbles and 188 large marbles.