Question

Given 10 < x + 12 Choose the solution set.
{x| x∈R, x > 2}
{x| x∈R, x < -2}
{x| x∈R, x > -2}
{x| x∈R, x < 2}
{x| x∈R, x > -4}

Answer 1

Answer:

{x| x∈R, x > -2}

Step-by-step explanation:

You solve the inequality just like you would solve an equality.

Everything that has the x on the left side, everything without x on the right side.

Be careful that when you multiply by -1, the inequality signal changes(for example, lesser than becomes higher than

So

$10 < x + 12$

$-x < 12 - 10$

$-x < 2$

Multiplying by -1

$x > -2$

So the correct answer is:

{x| x∈R, x > -2}

Answer 2

{x| x∈R, x > -2}

Step-by-step explanation:

You solve the inequality just like you would solve an equality.

Everything that has the x on the left side, everything without x on the right side.

Be careful that when you multiply by -1, the inequality signal changes(for example, lesser than becomes higher than

So

Multiplying by -1

So the correct answer is:

{x| x∈R, x > -2}