Question

I'LL GIVE BRAINLIEST....PLZ HELP ME!!
Solve the following system of equations using substitution. Be sure to show all work and check your answer.

y=5x+2

3x=-y+10

Answer 1

Answer:

Step-by-step explanation:

y = 5x + 2.....so we will sub in 5x + 2 for y, back into the other equation

3x = -y + 10

3x = - (5x + 2) + 10

3x = -5x - 2 + 10

3x + 5x = 8

8x = 8

x = 8/8

x = 1

y = 5x + 2

y = 5(1) + 2

y = 5 + 2

y = 7

check it... (1,7)

3x = -y + 10                           y = 5x + 2

3(1) = -7 + 10                          7 = 5(1) + 2

3 = 3 (correct)                       7 = 7 (correct)

so ur solution is : x = 1 and y = 7...or (1,7) <=====

Answer 2

Answer:

(1,7)

Step-by-step explanation:

Since we know that y=5x+2, we replace y in the bottom equation with 5x+2.

3x=-(5x+2)+10

Then distribute the - into both of the parentheses (multiply both terms by -1):

3x=-5x-2+10

Then add like terms:

3x=-5x+8

Add 5x to both sides:

8x=8

Divide both sides by 8:

x=1

Plug the known x value into y=5x+2:

y=5(1)+2

Multiply:

y=5+2

Add:

y=7

Put values into (x,y) form:

(1,7)