Respuesta :
Yo sup??
Since there is an x^2 term therefore this equation is of a parabola
By taking LCM and then cross multiplying it.
6y=x^2-9x+26
6y=x^2-9x+(9/2)^2+23/4
6y-23/4=(x-9/2)^2
we see that this is of the form
X^2=4AY
(x-9/2)^2=4(3y/2-23/16)
Hope this helps.
Answer:
[tex]f(x) =- \sqrt{x-1}+3[/tex]
Step-by-step explanation:
This looks like a square root function [tex]f(x) = \sqrt{x}[/tex] but symmetric with respect to the x axis and shifted to the right for 1 and up for 3:
Lets take [tex]f(x) = \sqrt{x}[/tex] . The function symmetric with respect to the x axis would be [tex]-f(x)[/tex], so now we have:
[tex]f(x) = -\sqrt{x}[/tex]
Lets take [tex]f(x) = -\sqrt{x}[/tex] and shift it up for y = 3. Now we have:
[tex]f(x) =- \sqrt{x}+3[/tex]
Lets take [tex]f(x) = -\sqrt{x}+3[/tex] and shift it right for x = 1. That means that instead of x we will have x-1:
[tex]f(x) =- \sqrt{x-1}+3[/tex]