As a science project, you drop a watermelon off the top of the Empire State Building, 320 m above the sidewalk. It so happens that Superman flies by at the instant you release the watermelon. Superman is headed straight down with a speed of 39.0 m/s.


How fast is the watermelon going when it passes Superman?

Respuesta :

Answer:

The velocity of watermelon when it passes Superman is 78 m/s.

Explanation:

Height of the building, d = 320 m

Speed of the superman, v = 39 m/s

We need to find the speed of watermelon when it passes Superman. Let t is the time taken by the watermelon. So,

[tex]d=ut+\dfrac{1}{2}gt^2[/tex]

Here u = 0

[tex]d=\dfrac{1}{2}gt^2[/tex]

[tex]39t=\dfrac{1}{2}\times 9.8\times t^2[/tex]

t = 7.95 seconds

Let v is the speed of the watermelon. It is given by :

[tex]v=gt[/tex]

[tex]v=9.8\times 7.95[/tex]

v = 77.91 m/s

or

v = 78 m/s

So, the velocity of watermelon when it passes Superman is 78 m/s.