Answer:
a.Velocity=[tex]\vec{v}=(6t)\hat{j}+8\hat{k}[/tex]
b.[tex]\vec{a}=6\hat{j}[/tex]
Explanation:
We are given that
A particle moves so that its position (in m) as function of time is
[tex]\vec{r}=2\hat{i}+(3t^2)\hat{j}+(8t)\hat{k}[/tex]
a.We have to find its velocity
We know that
Velocity,[tex]v=\frac{dr}{dt}[/tex]
Using the formula
Velocity,v=[tex]\frac{d(2i+3t^2j+8tk)}{dt}[/tex]
Velocity=[tex]\vec{v}=(6t)\hat{j}+8\hat{k}[/tex]
b.Acceleration[tex]=\vec{a}=\frac{d\vec{v}}{dt}[/tex]
[tex]\vec{a}=\frac{d((6t)\hat{j}+8\hat{k})}{dt}[/tex]
[tex]\vec{a}=6\hat{j}[/tex]