Question

Find and equation for the line with the given properties. Express the equation in general form. Slope -6/7; containing the point (10,-9) what is the equation for the line?

Answer 1

Answer:

$6x+7y+3=0$

Step-by-step explanation:

We are asked to find the equation of the line in general form, which has a of -6/7 and containing the point (10,-9).

We know that genera equation of a line is in form $Ax+By+C=0$, where, A, B and C are real numbers.

First of all, we will write our equation in point-slope form as:

$y-y_1=m(x-x_1)$, where,

m = Slope of line,

$(x_1,y_1)$ = Given point on line.

$y-(-9)=-\frac{6}{7}(x-10)$

$y+9=-\frac{6}{7}x+\frac{60}{7}$

$y*7+9*7=-\frac{6}{7}x*7+\frac{60}{7}*7$

$7y+63=-6x+60$

$6x+7y+63-60=-6x+6x+60-60$

$6x+7y+3=0$

Therefore, our required equation would be $6x+7y+3=0$.