Question

Find two consecutive even integers such that the sun of the larger and twice the smaller is 62.

Answer 1

Answer:

20 and 22.

Step-by-step explanation:

Let the consecutive integers be a and b

Then b = a + 2

a is the smaller integer.

$\begin{array}{rcl}2a + b & = & 62\\2a + a + 2& = & 62\\3a + 2 & = & 62\\3a & = & 60\\a & = & \dfrac{60}{3}\\\\& = & \mathbf{20}\\\end{array}$

a               = 20

b = 20 + 2 = 22

The two integers, in ascending order, are 20 and 22.

Check:

2(20) + 22 = 62

    40 + 22 = 62

             62 = 62

OK.