Answer:
NiCl2 (aq) + Na2CO3 (aq) ---> NiCO3 (s) + 2NaCl (aq)
Explanation:
Soluble ionic compounds exist as ions in solution.
Na 2CO3, will contain Na2CO3 (aq) --> 2Na ^+ (aq) + CO2 ^-3 (aq)
The same way, a solution of calcium chloride,
CaCl 2, will contain CaCl2 (aq) --> Ca2^+ (aq) + 2Cl^− (aq)
Mixing both solution, the calcium cations
Ca 2^+ , will apir up with the carbonate anions, CO2^−3 , and form the Insoluble calcium carbonate, CaCO ^3, which precipitates out of solution.
The complete ionic equation, which features all the ions that are present in solution, will be like this
2 Na^+ (aq) + CO2^−3 (aq) + Ca2^+ (aq) + 2Cl^− (aq) --> CaCO 3 ↓ (s) + 2Na^+ (aq) + 2Cl^− (aq)
Notice that you have two sodium cations and two chloride anions on the products' side, which is why you have 2NaCl
NiCl2 (aq) + Na2CO3 (aq) ---> NiCO3 (s) + 2NaCl (aq)
