The distance between two charges and is r, and the force between them is F. What is the force between them if the distance between them is doubled? a. F/4 c. 9F b. 4F d. F/9
The force between them if the distance between them is doubled is a. F/4
Explanation:
To find the answer, we can use Coulomb's law where it is defined as the force between two point charges is directly proportional to the magnitude of the point charges and proportional inversely to the distance between them.
The equation can be written as, [tex]F= K \frac{ q_{1} q_{2} }{r^{2} }[/tex] where k is the Coulomb constant, [tex]q_{1} q_{2}[/tex] are the point charges, and r is the distance between these two point charges.
To find the answer to this question, just substitute 2r in the place of r hence, you will get [tex]\frac{F}{4}[/tex] as the new force when the distance is doubled.
