Question

5. In a physics lab, an artifact is dropped from the roof of the school
building, 98 feet above the ground. The height h (in feet) of the ball
above the ground is given by the function h(t) = - 16t2 + 98, where t is the
time in seconds.
Part A:
Graph the function.
167² +98

Answer 1

Explanation:

The function is $h(t)=-16 t^{2}+98$

To graph the function, let us find the coordinates of the function $h(t)=-16 t^{2}+98$

For $t=-2$,

$\begin{aligned}h(t) &=-16(-2)^{2}+98 \\&=-16(4)+98 \\&=-64+98 \\&=34\end{aligned}$

The ordered pair is $(-2,34)$

For $t=-1$,

$\begin{aligned}h(t) &=-16(-1)^{2}+98 \\&=-16(1)+98 \\&=-16+98 \\&=82\end{aligned}$

The ordered pair is $(-1,82)$

For $t=0$,

$\begin{aligned}h(t) &=-16(0)^{2}+98 \\&=98\end{aligned}$

The ordered pair is $(0,98)$

For $t=1$,

$\begin{aligned}h(t) &=-16(1)^{2}+98 \\&=-16(1)+98 \\&=-16+98 \\&=82\end{aligned}$

The ordered pair is $(1,82)$

For $t=2$,

$\begin{aligned}h(t) &=-16(2)^{2}+98 \\&=-16(4)+98 \\&=-64+98 \\&=34\end{aligned}$

Thus, plotting these ordered pairs we get the graph of the function. The image of the graph is attached below.