The work done is 69.2 J
Explanation:
The work done by a force when pushing an object is given by
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem, we have:
F = 15.3 N is the force applied
d = 4.52 m is the displacement of the bookshelf
[tex]\theta=0[/tex] (assuming the force is applied in the direction of motion)
Therefore, the work done is:
[tex]W=(15.3)(4.52)(cos 0)=69.2 J[/tex]
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