Question

A ball initially at rest rolls down a hill and has an acceleration of 3.3 m/s². If it accelerates for 7.5 s, how far will it move during this time?
F. 12 m
G. 93 m
H. 120 m
J. 190 m

Answer 1

Answer:

G. 93 m

Explanation:

Applying the equation of motion,

s = ut + 1/2at²........................ Equation 1

Where s = distance, u = initial velocity, t = time, a = acceleration.

Given: u = 0 m/s ( at rest), a = 3.3 m/s², t = 7.5 s.

Substitute into equation 1

s = 0(7.5) + 1/2(3.3)(7.5)²

s = 0 + 185.625/2

s = 185.625/2

s = 92.8

s ≈ 93 m

Hence the right option is G. 93 m