Question

In the diagram, the length of segment VS is 39 units.
What is the length of segment TV?
3x + 4
14 units
19 units
38 units
50 units
2x + 5
6x - 3
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Answer 1

Answer:

$TV=38\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The figure shows a kite

The kite has two pairs of consecutive and congruent sides and the diagonals are perpendicular

That means

TS=VS

TQ=VQ

TR=RV

we have

$VS=39\ units$

$TS=6x-3$

so

$6x-3=39$

solve for x

$6x=39+3\\6x=42\\x=7$

Find the value of RV

$RV=2x+5$

substitute the value of x

$RV=2(7)+5=19\ units$

Remember that

$TV=TR+RV$ ---> by segment addition postulate

we have

$TR=RV=19\ units$

so

$TV=19+19=38\ units$