Question

Two copper wires have the same length but different cross sectional areas. The cross-sectional area of wire 1 is , and that of wire 2 is . How are the resistances of the two wires related

Answer 1

Explanation:

We know that resistance

$R= \frac{\rho L}{A}$

clearly,

R∝ 1/A

Greater the area cross section area of the.

therefore,

$\frac{R_1}{R_2} = \frac{A_2}{A_1} =\frac{d_2}{d_1}^2$