Answer: c. 0.9850
Step-by-step explanation:
Since the salaries for coffee shop baristas have a normal distrbution, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = salaries for coffee shop baristas.
µ = mean salary
σ = standard deviation
From the information given,
µ = $16164
σ = $1459
We want to find the probability that a randomly selected barista has a salary greater than $13,000. It is expressed as
P(x > 13000) = 1 - P(x ≤ 1300)
For x = 1300,
z = (1300 - 16164)/1459 = - 2.17
Looking at the normal distribution table, the probability corresponding to the z score is 0.015
P(x > 13000) = 1 - 0.015 = 0.985