What mass, in grams, of aluminum fins could 2571 J of energy heat from 15.73 ∘C to 26.50 ∘C ? Aluminum has a specific heat of 0.897 (J/g)⋅∘C. Express your answer to three significant figures.

Respuesta :

Answer:

266 g or 0.266 kg

Explanation:

The formula for specific heat capacity is given as,

Q = cm(t₂-t₁) ..................... Equation 1

Where Q = Heat Energy, c = specific heat capacity of Aluminum, m = mass of the aluminum fins, t₁ = initial temperature, t₂ = final temperature.

make m the subject of the equation,

m = Q/c(t₂-t₁)................... Equation 2

Given : Q = 2571 J, c = 0.897 J/g.°C, t₁ = 15.73 °C, t₂ = 26.50 °C.

Substitute into equation 2

m = 2571/[0.897×(26.5-15.73)]

m = 2571/9.661

m = 266 g or 0.266 kg

Hence the mass of the Aluminum fins = 266 g or 0.266 kg