Question

If the average speed of an orbiting space shuttle is 27 800 km/h, determine the time required for it to circle Earth. Assume that the shuttle is orbiting about 320.0 km above Earthâs surface, and that Earthâs radius is 6380 km.

Answer 1

Answer:

 t = 1.51 hours

Explanation:

given,

Speed of space shuttle. v = 27800 Km/h

Radius of earth, R = 6380 Km

height of shuttle above earth, h = 320 Km

Total radius of the shuttle orbit

r' = R + h

r' = 6380 + 320

r' = 6700 Km

distance, d = 2 π r

   d = 2 π x 6700

$time = \dfrac{distance}{speed}$

$time = \dfrac{2\pi\times 6700}{27800}$

 t = 1.51 hours

Time require by the shuttle to circle the earth is equal to 1.51 hr.

Answer 2

The mass of the space shuttle is negligible. The time required for it to circle Earth is 1.5 hours

Given that the average speed of an orbiting space shuttle is 27 800 km/h, from this question, the following parameters are given:

• Speed V = 27800 km/h

• The radius r = 320 + 6380 = 6700 Km

Whatever the masses of satellites, they will travel at the same speed in a particular orbit. The mass doesn't really have effect in the orbit.

The relationship between linear speed (V) and the angular speed (W) is

V = Wr

V = 2$\pi$r / T

Make T the subject of formula

T = 2$\pi$r / V

Substitute all the given parameters

T = (2 x $\pi$ x 6700) / 27800

T = 42097.34 / 27800

T = 1.5 hours

Therefore, the time required for it to circle Earth is 1.5 hours

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