Consider the Van der Vaals equation of state: (????+????????????)(????−????)=???????????? where p is pressure, V is volume, n is number of moles, T is absolute temperature, R is the gas constant and a and b are constants. What are the dimensions of a and b?

Respuesta :

Answer:

Units of a = [tex]\frac{atm\ L^2}{mol^2}[/tex]

Units of b = [tex]\frac{L}{mol}[/tex]

Explanation:

The Van der Waal's equation  is:-

[tex]\left(P+\frac{an^2}{V^2}\right)\left(V-nb\right)=nRT[/tex]

Where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value

a and b are van der Waal's constant

If pressure is taken in atm and volume in L. So,

[tex]P+\frac{an^2}{V^2}[/tex] represents the pressure correction term. Then,

Units of a = [tex]\frac{atm\ L^2}{mol^2}[/tex]

[tex]V-nb[/tex] represents the volume correction term. Then,

Units of b = [tex]\frac{L}{mol}[/tex]