Question

A 3-kg object is moving at 5.0 m/s. An 12-N force is applied in the direction of motion and then removed after the object has traveled an additional 6.0 m. The work done by this force is:

Answer 1

Answer:

Work done by applied force will be equal to 72 J    

Explanation:

We have given force applied on the object F = 12 N

Distance traveled by object due to applied force s = 6 m

We have to find the work done by the applied force

Work done due to applied force is equal to product of force applied and distance traveled

So work done will be equal to $W=fs=12\times 6=72J$

So work done by applied force will be equal to 72 J