Question

NEED HELP ASAP PLEASE

Answer 1

Answer:

13.896 kg

Step-by-step explanation:

The area of a trapezium can be worked out by the equation:

$area = \frac{1}{2} (a+b)h$

So the area is equal to:

$\frac{1}{2} (6+12)$ × 5 = 45 cm²

The volume is 45 × 16 = 720 cm³

The mass of the gold bar is equal to 720 × 19.3 = 13896 g

This is 13.896 kg

Answer 2

Step-by-step explanation:

▪ density = mass/volume

▪ volume =

$\frac{6 + 12}{2} \times 5 \times 16 = 720cm {}^{2}$

▪ density in kcm3 = 19.3 ÷ 1000 = 0.0193

▪ mass = density × volume = 0.0193 × 720 = 13.896kg