Question

Sachi wants to throw a water balloon to knock over a target and win a prize. The target will only fall over if it is hit with a force of 0.035 N. The water balloon has a mass of 11.4 grams. How fast will Sachi have to make the water balloon accelerate to hit the target with enough force and win the prize?
Round the answer to the nearest one tenth m/s2.
The water balloon must accelerate m/s2.

Answer 1

Answer:

3.1 m/s²

Explanation:

Given:

Mass of the balloon (m) = 11.4 g = 0.0114 kg ( 1 kg = 1000 g)

Force acting on the balloon (F) = 0.035 N

Acceleration with which the balloon must be hit (a) = ?

Now, we know that, from Newton's second law, net force acting on an object is equal to the product of its mass and acceleration.

Therefore, framing in equation form, we have:

$F=ma$

Rewriting in terms of acceleration 'a', we get:

$a=\frac{F}{m}$

Now, substitute the given values and solve for 'a'. This gives,

$a=\frac{0.035\ N}{0.0114\ kg}\\\\a=3.07\approx 3.1\ m/s^2(Nearest\ tenth)$

Therefore, the acceleration of the water balloon to reach the target must be equal to 3.1 m/s².

Answer 2

Answer:

3.1

Explanation:

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