Question

A chemist mixes 65.6 g of ethanol with 15.1 g of acetone and 99.6 g of 4-methyl-2-pentanone. Calculate the percent by mass of each component of this solution. Round each of your answers to 3 significant digits

Answer 1

Answer:

Ethanol = 36.4%

Acetone = 8.37%

4-methyl-2-pentanone = 55.2%

Explanation:

Mass of ethanol = 65.6g

Mass of acetone = 15.1g

Mass of 4-methyl-2-pentanone = 99.6g

Total Mass = 65.6 + 15.1 + 99.6 = 180.3g

% Mass of ethanol = (65.6/180.3) x 100 = 36.4%

% Mass of acetone = (15.1/180.3) x 100 = 8.37%

% Mass of 4-methyl-2-pentanone = (99.6/180.3) x 100 = 55.2%

Answer 2

The percent by mass of each chemical component of this solution:

1. 36.4% for ethanol.

2. 8.38% for acetone.

3. 55.2% for 4-methyl-2-pentanone.

Given the following data:

• Mass of ethanol = 65.6 grams

• Mass of acetone = 15.1 grams

• Mass of 4-methyl-2-pentanone = 99.6 grams

To calculate the percent by mass of each chemical component of this solution:

First of all, we would determine the total mass of the solution.

$Total \;mass = 65.6 + 15.1 + 99.6\\\\Total\;mass = 180.3\;grams$

Now, we can calculate the percent by mass of each chemical component of this solution by using this formula:

$Percent\;mass = \frac{Mass\;of\;substance}{Total\;mass} \times 100$

For ethanol:

$Percent\;mass = \frac{65.6}{180.3} \times 100\\\\Percent\;mass = \frac{6560}{180.3}$

Percent by mass = 36.4%

For acetone:

$Percent\;mass = \frac{15.1}{180.3} \times 100\\\\Percent\;mass = \frac{1510}{180.3}$

Percent by mass = 8.38%

For 4-methyl-2-pentanone:

$Percent\;mass = \frac{99.6}{180.3} \times 100\\\\Percent\;mass = \frac{9960}{180.3}$

Percent by mass = 55.2%

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