To solve this problem we will apply the concepts related to the Doppler effect. According to this concept, it is understood as the increase or decrease of the frequency of a sound wave when the source that produces it and the person who captures it move away from each other or approach each other. Mathematically this can be described as
[tex]f = f_0 (\frac{v-v_0}{v})[/tex]
Here,
[tex]f_0[/tex] = Original frequency
[tex]v_0[/tex] = Velocity of the observer
[tex]v[/tex] = Velocity of the speed
Our values are,
[tex]v = 340m/s \rightarrow \text{Speed of sound}[/tex]
[tex]f = 20kHz \rightarrow \text{Apparent frequency}[/tex]
[tex]f_0 = 21kHz \rightarrow \text{Original frequency}[/tex]
Using the previous equation,
[tex]f = f_0 (\frac{v-v_0}{v})[/tex]
Rearrange to find the velocity of the observer
[tex]v_0 =v (1-\frac{f}{f_0})[/tex]
Replacing we have that
[tex]v_0= (340m/s)(1-\frac{20kHz}{21kHz})[/tex]
[tex]v_0 = 16.19m/s[/tex]
Therefore the velocity of the observer is 16.2m/s