Answer:B
Explanation:
Given
Power Produced [tex]P=25\ kW[/tex]
time [tex]t=10\ min[/tex]
Gasoline consumed [tex]m=1.25\ kg[/tex]
Heat capacity of Gasoline [tex]C=43,000\ kJ/kg[/tex]
Heat Provided by Gasoline [tex]Q_s=m\times C[/tex]
[tex]Q_s=1.25\times 43000=53,750\ kJ[/tex]
Energy used in Producing Power is [tex]W=25\times 10\times 60=15,000\ kJ[/tex]
Efficiency of an engine is
[tex]\eta =\frac{Work}{Energy\ Supplied}[/tex]
[tex]\eta =\frac{15000}{53750}=0.2790[/tex]
[tex]\eta =27.90\approx 28\ \%[/tex]