Answer:
He have 42 oranges and 7 mangoes.
The correct answer is 7 mangoes and 42 oranges.
Step-by-step explanation:
Given:
Renaldo has six times as many oranges as mangoes. He has 49 pieces of fruit in all. Let r represent the number of oranges and m represent the number of mangoes.
Now to find the number of each fruit Renaldo have.
As, given:
Let [tex]r[/tex] represent the number of oranges and [tex]m[/tex] represent the number of mangoes.
So, as he has six times as many oranges as mangoes.
Thus,
[tex]r=6m[/tex] ..........( 1 )
Total number of fruits = 49.
According to question:
[tex]m+r=49[/tex]
Substituting the value of [tex]r[/tex] from equation (1) we get:
[tex]m+6m=49[/tex]
[tex]7m=49[/tex]
Dividing both sides by 7 we get:
[tex]m=7.[/tex]
Number of mangoes = 7.
Now, to get the number of oranges we put the value of [tex]m[/tex] in equation (1):
[tex]r=6m[/tex]
[tex]r=6\times 7[/tex]
[tex]r=42.[/tex]
The number of oranges = 42.
Therefore, he have 42 oranges and 7 mangoes.
The correct answer is 7 mangoes and 42 oranges.
