Answer:
b. 56
Step-by-step explanation:
Please consider the complete question.
There are 8 members on a board of directors. If they must form a subcommittee of 3 members, how many different subcommittees are possible?
We will use combinations for solve our given problem.
[tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex], where,
n = Number of total items,
r = Items being chosen at a time.
For our given scenario [tex]n=8[/tex] and [tex]r=3[/tex].
[tex]^8C_3=\frac{8!}{3!(8-3)!}[/tex]
[tex]^8C_3=\frac{8!}{3!\cdot 5!}[/tex]
[tex]^8C_3=\frac{8\cdot7\cdot6\cdot5!}{3\cdot2\cdot1\cdot 5!}[/tex]
[tex]^8C_3=8\cdot7[/tex]
[tex]^8C_3=56[/tex]
Therefore, 56 different subcommittees are possible and option 'b' is the correct choice.