Answer:
The approximate margin of error = ± 0.1131607
Step-by-step explanation:
By margin of error = ± Z *[tex]\sqrt{\frac{p(1-p)}{n} }[/tex]
We assume 95% confidence interval. Thus Z = 1.96. Since the survey is about support or oppose, we assume equal proportion: 50% for and 50% against.
Hence, margin of error = ± 1.96* ((0.5*0.5)/75)^(0.5)
= ± 0.1131607