Question

A person applies an impulse of 5.0 kg m/s to a box in order to set it in motion. If the person is in contact with the box for 0.25 s, what is the average force exerted by the person on the box? a. 1.25N b. 2.00 N c. 12.5 N d. 20.0 NN e. 200 N

Answer 1

Answer:

The average force exerted by the person on the box is 20 N.                    

Explanation:

Given that,

Impulse applied to the box, m = 5 kg-m/s

Time of contact of the person with the box is 0.25 seconds. We need to find the average force exerted by the person on the box. The impulse applied on an object is given by :

$J=F\times t$

F is the average force exerted by the person on the box

$F=\dfrac{J}{t}$

$F=\dfrac{5\ kg-m/s}{0.25\ s}$

F = 20 N

So, the average force exerted by the person on the box is 20 N. Hence, this is the required solution.