Answer:
Drag force=3.5g N
Greater
Explanation:
We know that from Newton’s law of motion, boots force, F=ma where m is mass and a is acceleration of the object
Given mass of 70 Kg and a=0.25g then jet boots exert a force of F=70*0.25g=17.5g
The net force is given by subtracting the net force from the force of jet boots
[tex]F_{boots}-F_{drag}=ma[/tex]
In the ship acceleration is limited to 0.2g. We also know that the drag force is directly proportional to velocity squared
ma=70*0.2g=14g N
Drag force= 17.5g-14g=3.5g N
When the velocity is increased to 20 m/s, drag force also increases since drag force is directly proportional to velocity squared