Question

One car travel 56 miles per hour and another travels 31 miles per hour. If they start from the same place at the same time and travel in the same direction, after how many hours will the faster car be 75 miles ahead of the slower car?

Answer 1

After 3 hours, the faster car will be 75 miles ahead of the slower car.

Step-by-step explanation:

Given,

Speed of first car = 56 miles per hour

Speed of second car = 31 miles per hour

Let,

x be the number of hours.

Distance covered by first car = Speed * time = 56x

Distance covered by second car = 31x

According to given statement;

Difference between distance covered by both cars = 75 miles

Distance of faster car - Distance of slower car = 75 miles

$56x-31x=75\\25x=75$

Dividing both sides by 25

$\frac{25x}{25}=\frac{75}{25}\\x=3$

After 3 hours, the faster car will be 75 miles ahead of the slower car.

Keywords: subtraction, division

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