Question

A line has a slope of 10 and includes the points (-3, -4) and (-2, r). What is the value of r?

Answer 1

Answer:

Step-by-step explanation:

slope = (y2 - y1) / (x2 - x1)

(-3,-4)....x1 = -3 and y1 = -4

(-2,r)....x2 = -2 and y2 = r

slope = 10

now sub

10 = (r - (-4) / (-2 - (-3)

10 = (r + 4) / (-2 + 3)

10 = (r + 4) / 1.....multiply both sides by 1, eliminating the 1 on the right

10 * 1 = r + 4

10 = r + 4

10 - 4 = r

6 = r <======

Answer 2

Answer:

6 = r

Explanation:

Slope = $(y2 - y1)/(x2 - x1)$

$(-3,-4)....x1 = -3$ and $y1 = -4$

$(-2,r)....x2 = -2$ and $y2 = r$

Slope = $10$

Now substitute.

$10 = (r - (-4) / (-2 - (-3)\\10 = (r + 4) / (-2 + 3)\\10 = (r + 4) / 1$

Multiply both sides by 1, eliminating the 1 on the right

$10 * 1 = r + 4\\10 = r + 4\\10 - 4 = r\\6 = r$