Question

Suppose you have Honda Civic that, along with passengers, has a mass of 1,298 kg. How much force does it take to achieve the acceleration needed to reach 27 m/s (60 mph) in 6 s?

Answer 1

The force required for the car is 5841 N

Explanation:

First of all, we need to find the acceleration of the car, which is given by:

$a=\frac{v-u}{t}$

where:

v = 27 m/s is the final velocity of the car

u = 0 is the initial velocity (the car starts from rest)

t = 6 s is the time the car takes to accelerate from u to v

Substituting, we find

$a=\frac{27-0}{6}=4.5 m/s^2$

Now we can find the force needed to accelerate the car; using Newton's second law of motion,

$F=ma$

where:

F is the net force on the car

m = 1298 kg is the mass of the car

$a=4.5 m/s^2$ is the acceleration

Substituting, we find:

$F=(1298)(4.5)=5841 N$

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