Question

ASAP! PLEASE HELP ASAP!! WILL MARK BRAINLIEST FOR FIRST ACCURATE ANSWER!!!
Using the given equation find the missing coordinates of the points and then find the slope of the line for each equation
c) y=− 2/3 x+ 1/6 ; A(...; 6), B(9; ...)

Answer 1

Answer:

Step-by-step explanation:

The slope for the equation is -2/3

y=-2/3x+1/6

6=-2/3x+1/6

x= -35/9

A(-35/9, 6)

y=-2/3x+1/6

y=-2/3(9)+1/6

y=-35/6

B(9,-35/6)

Answer 2

Answer:

Step-by-step explanation:

y = − 2/3 x+ 1/6......(1)

Comparing with y = mx + c

Slope m = -2/3

Let A(...; 6) be A(a; 6)

y1 = 6 and x1 = a

y - y1 = m(x - x1)

y - 6 = -2/3(x - a)

Multiply each term by 3

3y - 18 = -2x - 2a

3y = -2x - 2a + 18

Dividing by 3

y = -2x/3 - 2a/3 + 6.......(2)

Equating (1) and (2)

− 2/3x+ 1/6 = -2x/3 - 2a/3 + 6

Collecting like terms

-2x/3 + 2x/3 + 2a/3 = 6 - 1/6

2a/3 = 6 - 1/6

Multiply each term by 6

4a = 36 - 1

4a = 35

a = 35/4

a = 8 3/4

A(35/4; 6)

Let B(9;....) Be B(9; b)

y2 = b, y1 = 6, x2 = 9, x1 = 35/4

Slope m = (y2 - y1)/(x2 - x1)

-2/3 = (b - 6)/(9 - 35/4)

Cross Multiply

-2(9 - 35/4) = 3(b - 6)

-18 + 35/2 = 3b - 18

Collecting like terms

-18 + 18 + 35/2 = 3b

3b = 35/2

b = 35/(2×3)

b = 35/6

b = 5 5/6

B(9; 35/6)