Answer:
Val is right
Step-by-step explanation:
One of the solutions to k < 3 is k = -4. When you square that, you get ...
k² = (-4)² = 16
which is not less than 9.
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k < 3 and k² < 9 will have the same solution set for |k| < 3, but their solution sets will differ for k ≤ -3.
When performing operations on inequalities, one needs to be aware of the order preserving/changing effects of the operation. Whether squaring a value preserves order or not depends on the relative magnitudes: