Respuesta :
Answer:
The the equation of the image of after a dilation with a scale factor of 3, centered at the origin will be [tex]y=\:-\:\frac{1}{3}x-9[/tex], which is shown as blue colored line in attached graph.
Step-by-step explanation:
Considering the equation of the line
[tex]y=\:-\:\frac{1}{3}x-3[/tex]
Comparing with the slope-intercept form [tex]y = mx + b[/tex], we can determine that the slope of line is [tex]m = \frac{-1}{3}[/tex], as shown in the attached figure. The red colored line indicated the this (original) line.
We have to write the equation of the image after a dilation with a scale factor of 3, centered at the origin.
Writing Steps:
- First draw the line of the equation as shown in attached figure.
- Then take a point from the line. Let suppose the point is (0, -3).
- Then dilate the point (0, -3) with a scale factor of 3 by multiplying the coordinates of the point (0, -3) with 3 to determine the location of the dilated point. So,
(x, y) ⇒ (3x, 3y)
(0, -3) ⇒ (3×0, 3×-3) = (0, -9)
Now, lets write the equation of new line
As the dilated line has same slope. So,
[tex]m = \frac{-1}{3}[/tex]
As the dilated point is (0, -9), in which
x = 0, and y = -9
As the slope-intercept form is
[tex]y = mx + b[/tex] where [tex]m = \frac{-1}{3}[/tex]
So, putting the values in slope intercept form
[tex]y = mx + b[/tex]
[tex]-9=\:-\:\frac{1}{3}\left(0\right)+b[/tex]
[tex]\mathrm{Switch\:sides}[/tex]
[tex]-\frac{1}{3}\left(0\right)+b=-9[/tex]
[tex]\mathrm{Remove\:parentheses}:\quad \left(a\right)=a[/tex]
[tex]-\frac{1}{3}\cdot \:0+b=-9[/tex]
[tex]\mathrm{Apply\:rule}\:0\cdot \:a=0[/tex]
[tex]-0+b=-9[/tex]
[tex]b=-9[/tex]
So, the equation of image becomes
[tex]y=\:-\:\frac{1}{3}x+\left(-9\right)[/tex]
[tex]y=\:-\:\frac{1}{3}x-9[/tex]
So, the the equation of the image of after a dilation with a scale factor of 3, centered at the origin will be [tex]y=\:-\:\frac{1}{3}x-9[/tex], which is shown as blue colored line in attached graph.
Keywords: equation, dilation, scale factor of 3
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