Question

$4(x - 1) {}^{2} - 9$
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Answer 1

Step-by-step explanation:

(a-b)^2=(a^2-2*a*b+b^2)

4*(x^2-2x+1)-9=4x^2-8x+4-9=4x^2-8x-5

if you have to calculate the Δ

there is it: 4x^2-8x-5=0

Δ=b^2-4*a*c=64-4*4*(-5)=64+80=144

$x_{1,2}=$-b±Δ/2*a=8±12/8=

$x_{1}$=8+12/8=20/8|:4=5/2

$x_{2}$=8-12/8=-4/8|:4=-1/2