Step-by-step explanation:
Surface area of cubic cell
[tex] = 6(side)^{2} \\ = 6 \times {4}^{2} \\ = 6 \times 16 \\ = 96 \: {mm}^{2} \\ \\ volume \: of \:cubic \: cell \\ = {(side)}^{3} \\ = {4}^{3} \\ = 64 \: {mm}^{3} \\
[/tex]
Ratio of surface area to volume of imaginary cubic cell
[tex] = \frac{96}{64}\\
= \frac{3}{2}\\
=3 : 2[/tex]
Answer:
3/2
Step-by-step explanation:
surface area = (2×base) +( height×base perimeter )
= (2×(4×4)) +( 4×(4×4) )
= 32 + 64
= 96 mm
volume = side³
= 4³
= 64 mm
the ratio of surface area to volume = 96/64 = 3/2
