Question

What is the energy change when the temperature of 14.8 grams of solid lead is decreased from 38.4 °C to 23.7 °C ?

Answer 1

Answer:

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Answer 2

Answer: -34.6 J

Explanation: solution attached:

c= 0.159 J/g°C for solid lead.

Use Q = mc∆T

= 14.8g( 0.159J/g°C) ( 23.7°C-38.4°C)

= - 34.6 J

The units for g and °C will be cancelled out and the remaining unit is in J.